Question

Find the zeroes of the polynomial $g\left(x\right)=7\sqrt{2}{x}^2-10x-4\sqrt{2}$

Answer 1

$7\sqrt{2}{x}^2-10x-4\sqrt{2}$

$x=\frac{-b+\sqrt{b^2-4ac}}{2a}$

$\frac{(-10)+\sqrt{100-4\left(7\sqrt{2}\right)(-4\sqrt{2})}}{14\sqrt{2}}$

$\frac{10+\sqrt{100+224}}{14\sqrt{2}}$

$\frac{10+\sqrt{324}}{14\sqrt{2}}$

$\frac{10+18}{14\sqrt{2}}$, $\frac{10-18}{14\sqrt{2}}$

$\frac{28}{14\sqrt{2}}$ ,$\frac{-8}{14\sqrt{2}}$

$\frac{2}{\sqrt{2}}$,$\frac{-4}{7\sqrt{2}}$

$=\sqrt{2}$ $\frac{-2\sqrt{2}}{7}$