Find the zeroes of the polynomial in each of the following:
$h (y) = 2 y$ .

0

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2 y

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y

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- 1

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Solution

The correct option is A $0$
We know, zero of $h (y) = 2 y$ will be when $h (y) = 0$ .
$⟹ 2 y = 0$
$⟹ y = 0$ .
Thus, $0$ is the zero of the polynomial.

Hence, the statement is true.

Therefore, option $A$ is correct.

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Similar questions

(i) p(x) = x – 4

(ii) g(x) = 3 – 6x

(iii) q(x) = 2x – 7

(iv) h(y) = 2y

(i) p(x) = x – 4

(ii) g(x) = 3 – 6x

(iii) q(x) = 2x – 7

(iv) h(y) = 2y

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p (y) = 2 + y + 2 y^{2} - y^{3}

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