Find the zeroes of the polynomial $m x^{2} + (m + n) x + n$

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Solution

$m x^{2} + m x + n x + n = 0 m x (x + 1) + n (x + 1) = 0 (m x + n) (x + 1) = 0 x = - \frac{n}{m} x = - 1$

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Similar questions

Q. Find the relation between

m

and

n

if the polynomial

f (x) = 2 x^{3} + m x^{2} + n x - 14

has a factor

(x - 1)

Q. If the polynomial

f (x) = 2 x^{3} + m x^{2} + n x - 14

has

(x - 1)

and

(x + 2)

as its factors, find the value of

\frac{m}{n}

Find the values of m and n in polynomial 2x³+MX²+nx-14 such that x-1and x+2 are it's factors

NX is produced by the following step of reactions M + $X_{2}$ $⟶$ $M X_{2}$ $⟶$ $M X_{2}$ + $X_{2}$ $⟶$ $M_{3} X_{8}$

$M_{3} X_{8}$ + $N_{2} C O_{3}$ $⟶$ NX + $C O_{2}$ + $M_{3} O_{4}$ How much M (metal) is consumed to produce 206 gm of NX. (Take at wt. of M = 56, N = 23, X = 80)

$N X$ is produced by the following step of reactions:

1. $M +$ $X_{2}$ $⟶$ $M X_{2}$

2. $M X_{2}$ + $X_{2}$ $⟶$ $M_{3} X_{8}$

3. $M_{3} X_{8}$ + $N_{2} C O_{3}$ $⟶$ $N X +$ $C O_{2}$ + $M_{3} O_{4}$

How much M (metal) is consumed to produce $206 g$ of $N X$ . (Take atomic weight of $M = 56, N = 23, X = 80$ )

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Find the zeroes of the polynomial mx2+(m+n)x+n

mx2+mx+nx+n=0mx(x+1)+n(x+1)=0(mx+n)(x+1)=0x=−nmx=−1

Find the zeroes of the polynomial $m x^{2} + (m + n) x + n$

$m x^{2} + m x + n x + n = 0 m x (x + 1) + n (x + 1) = 0 (m x + n) (x + 1) = 0 x = - \frac{n}{m} x = - 1$