Question

Find the zeroes of the polynomial :
$p\left(x\right)=(x-2{)}^2-(x+2{)}^2$.

• A. $-1$
• B. $1$
• C. $0$
• D. Non zero Integers

Answer 1

Answer: (C)

$0$

Given polynomial $p\left(x\right)=(x-2{)}^2-(x+2{)}^2$.
To find the zeros of $p\left(x\right)$, we have $p\left(x\right)=0$.
$\Rightarrow (x-2{)}^2-(x+2{)}^2=0$
$\Rightarrow x^2+4-4x-x^2-4-4x=0$
$\Rightarrow -8x=0$
$\Rightarrow x=0$.
Thus, the zeros of the polynomial is $0$.

Therefore, option $C$ is correct.