Question

Find the zeroes of the polynomial:

$x^2-2x-8$.

Answer 1

Splitting the middle term:

$x^2-2x-8$$=x^2-4x+2x-8=0$

$=(x-4)(x+2)$

Equating the above expression equal to $0$ to find the zeroes:

$(x-4)(x+2)=0$

$x-4=0$ or $x+2=0$

$x=4$ or $x=-2$

Thus, zeroes of the polynomial is $4,-2$.