Question

Find the zeroes of the polynomial xsquare -3 and verify the relationship between the zeroes and the coefficients

Answer 1

First we have to compare the given equation with the general form of a x² + b x + c

Let p(x) = x^2-3

So, p(x) = 0
x^2-3=0
x^2=3
x=+√3 or -√3

Hence the zeroes of p(x) are +√3and -√3

Thus, Sum of zeroes = 0 and the product of zeroes = -3

From the basic relationships, we get

The sum of the zeroes = -coefficient of x/coefficient of x²

= -(0/1)
=0

The product of the zeroes = constant term/coefficient of x²

=-3/1
=-3

Thus the basic relationship verified.
read it carefully.
hope you understood.