Let, f(x)=3x2−75=0
⇒3x2−75=0
⇒x2−25=0
⇒(x−5)(x+5)=0
⇒x=−5,5
So, zeros of quadratic equation are 5 and −5
Verification:
Sum of zeros =−coeficient of xcoeficient of x2
⇒0=−03
⇒0=0
And,
Product of zero =constant termcoeficient of x2
⇒5×−5=−753
⇒−25=−25
Hence, verified.