Find the zeroes of the quadratic polynomial and verify the relationship between zeroes and coefficients
6x²-3-7x

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Solution

let 6x2-7x-3 be p(x) =0
so,6x2-7x-3 =0
6x2-(9-2)x-3
6x2-9x+2x-3
(6x2-9x)(2x-3)
3x(2x-3)+1(2x-3)
(3x+1)(2x-3)=0
3x+1=0 2x-3=0
x=-1/3 x=3/2
sum of zeroes=-1/3+3/2 =7/6 =-b/a
product of zeroes=-1/3*3/2 = -3/6 or -1/2=c/a
hence verified.........

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