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Question
Find the zeroes of x3+11x2+23x−35 If two of its zeros are 1 and −5.
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Solution
x3+11x2+23x−35.=0.......(1)Given two zero of equation 1 are 1 , & -5 if α,β,γ are zero of equation 1. the now α,β,γ=−11,α=−11−(β+γ)=−11−(1−5)α=−11+4[α=−7]Hence its third zero is -7
x3+11x2+23x−35.=0.......(1)
Given two zero of equation 1 are 1 , & -5 if α,β,γ are zero of equation 1. the
now α,β,γ=−11,
α=−11−(β+γ)=−11−(1−5)
α=−11+4
[α=−7]
Hence its third zero is -7
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