Find the zeros and verify the relationship between zero's and the coefficients of xsquare-2x-8

Open in App

Solution

X^2 -2x-8=0
X^2 +2x-4x-8=0
X(x+2)-4(x+2)=0
(X+2)(x-4)=0
X=-2,4

Sum of zeroes=-2+4=2=(--2/1)=(-b/a)
Product of zeroes=-2*4=-8=(-8/1)=(c/a)

Where a,b are cofficients of x^2 and x respectively and c is the constant

Suggest Corrections

Similar questions

Find the zeroes of the polynomial xsquare -3 and verify the relationship between the zeroes and the coefficients

Q. Find the zeros of the following quadratic polynomial and verify the relationship between the zeros and the coefficients.

x^{2} - 2 x - 8

Q. Find the zeros of the following quardric polynomials and verify the relationship between the zeroes and the coefficients.
i)

x^{2} - 2 x - 8

Q. Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients

x^{2} - 2 x - 8

Question 1 (i)
Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients.
$x^{2} - 2 x - 8$

Join BYJU'S Learning Program

Find the zeros and verify the relationship between zero's and the coefficients of xsquare-2x-8

X^2 -2x-8=0 X^2 +2x-4x-8=0 X(x+2)-4(x+2)=0 (X+2)(x-4)=0 X=-2,4 Sum of zeroes=-2+4=2=(--2/1)=(-b/a) Product of zeroes=-2*4=-8=(-8/1)=(c/a) Where a,b are cofficients of x^2 and x respectively and c is the constant

X^2 -2x-8=0
X^2 +2x-4x-8=0
X(x+2)-4(x+2)=0
(X+2)(x-4)=0
X=-2,4

Sum of zeroes=-2+4=2=(--2/1)=(-b/a)
Product of zeroes=-2*4=-8=(-8/1)=(c/a)

Where a,b are cofficients of x^2 and x respectively and c is the constant