Question

find the zeros of 4x​²+ 5 under root 2-3

Answer 1

$$\begin{gathered} 4{\mathrm{x}}^2+5\sqrt{2}\mathrm{x}-3=0 \\ \mathrm{Splitting}\mathrm{the}\mathrm{middle}\mathrm{term} \\ 4{\mathrm{x}}^2+6\sqrt{2}\mathrm{x}-\sqrt{2}\mathrm{x}-3=0 \\ 2\sqrt{2}\mathrm{x}\left(\sqrt{2}\mathrm{x}+3\right)-1\left(\sqrt{2}\mathrm{x}+3\right)=0 \\ \left(2\sqrt{2}\mathrm{x}-1\right)\left(\sqrt{2}\mathrm{x}+3\right)=0 \\ 2\sqrt{2}\mathrm{x}-1=0\mathrm{and}\sqrt{2}\mathrm{x}+3=0 \\ \mathrm{x}=\frac{1}{2\sqrt{2}}\mathrm{and}\mathrm{x}=-\frac{3}{\sqrt{2}} \\ \mathrm{So},\mathrm{zeros}\mathrm{are}\frac{1}{2\sqrt{2}}\mathrm{and}-\frac{3}{\sqrt{2}}. \end{gathered}$$