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Solving a Quadratic Equation by Completion of Squares Method

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Question

Find the zeros of polynomial $6 x^{2} - 3 - 7 x$ .

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Solution

$6 x^{2} - 7 x - 3 = 0$

$6 x^{2} - 9 x + 2 x - 3 = 0$

$3 x (2 x - 3) + 1 (2 x - 3) = 0$

$(2 x - 3) (3 x + 1) = 0$

$x = \frac{3}{2}, - \frac{1}{3}$

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