Find the zeros of the equation $x^{2} + x + 1$ .

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Solution

Now,
$x^{2} + x + 1 = 0$ gives,
$x = \frac{- 1 \pm \sqrt{1 - 4}}{2}$
or, $x = \frac{- 1 \pm \sqrt{3} i}{2}$ .
So $\frac{- 1 \pm \sqrt{3} i}{2}$ are the zeros of the given polynomial.

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