Question

Find the zeros of the following polynomial
(c.) x^2-5

Answer 1

$$\begin{gathered} \mathrm{Let}\mathrm{p}\left(\mathrm{x}\right)={\mathrm{x}}^2-5 \\ \mathrm{Now},\mathrm{zeroes}\mathrm{of}\mathrm{p}\left(\mathrm{x}\right)\mathrm{are}\mathrm{given}\mathrm{by}\mathrm{solving}\mathrm{the}\mathrm{equation}, \\ {\mathrm{x}}^2-5=0 \\ \Rightarrow {\left(\mathrm{x}\right)}^2-{\left(\sqrt{5}\right)}^2=0 \\ \Rightarrow \left(\mathrm{x}+\sqrt{5}\right)\left(\mathrm{x}-\sqrt{5}\right)=0 \\ \Rightarrow \mathrm{x}+\sqrt{5}=0\mathrm{or}\mathrm{x}-\sqrt{5}=0 \\ \Rightarrow \mathrm{x}=-\sqrt{5}\mathrm{or}\mathrm{x}=\sqrt{5} \end{gathered}$$