Question

Find the zeros of the following polynomial:

$p\left(x\right)=x-2$

Answer 1

A polynomial is a function of the form $f\left(x\right)=a_n{x}^n+a_{n-1}{x}^{n-1}+...+a_2{x}^2+a_{1}x+a_0$ .

where $a_n,a_{n-1},...a_2,a_1,a_0$ . are contants

and $n$ is a natural number.

To find zeroes :

$p\left(x\right)=0$

Given that polynomial is

$p\left(x\right)=x-2$

to find zero of given polynomial

$p\left(x\right)=x-2=0$

$\Rightarrow x-2=0$

$\Rightarrow x=2$

Hence, $2$ is the Zero of given polynomial $p\left(x\right)$