Find the zeros of the polynomial $6 + x^{2} - 5 x$

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Solution

Let $p (x) = x^{2} - 5 x + 6$

$= x^{2} - 3 x - 2 x + 6$

$= x (x - 3) - 2 (x - 3)$

$p (x) = (x - 3) (x - 2)$

To find zero of $p (x)$ we equate $p (x)$ to $0$ and find $x$ .

Let $p (x) = 0$

$\Rightarrow (x - 3) (x - 2) = 0$

$\Rightarrow x = 3 o r 2$

Hence $2, 3$ are the zeroes of $x^{2} - 5 x + 6$

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x^{2} - 5 x + 6

find the zero's of polynomial $P (x) = x^{2} - 5x + 6$

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