Find the zeros of the polynomial $x^{2} + x - p (p + 1)$

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Solution

$x^{2} + x - p (p + 1) = 0$

$\Rightarrow x^{2} + (p + 1) x - p x - p (p + 1) = 0$

$\Rightarrow x (x + (p + 1)) - p (x + (p + 1)) = 0$

$\Rightarrow (x - p) (x + (p + 1)) = 0$

$\Rightarrow x - p = 0$ OR $x + (p + 1) = 0$

$\Rightarrow x = p$ OR $x = - (p + 1)$

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Similar questions

Find the zeros of the polynomial $x^{2} + x - p (p + 1)$ .

p (x) = x^{2} - 1

If $α$ and $β$ are the zeros of the polynomial $f (x) = x^{2} + x - 2$ , find the value of $(\frac{1}{α} - \frac{1}{β})$ .

3 \sqrt{2} x^{2} + x - \sqrt{2}

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