Find the zeros of the quadratic polynomial $5 x^{2} - 4 - 8 x$

3

and

\frac{- 2}{5}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

7

and

\frac{- 2}{5}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2

and

\frac{- 2}{5}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

5

and

\frac{- 2}{5}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $2$ and $\frac{- 2}{5}$
$5 x^{2} - 4 - 8 x$
$= 5 x^{2} - 8 x - 4$
$= 5 x^{2} - 10 x + 2 x - 4$
$= 5 x (x - 2) + 2 (x - 2)$
$= (x - 2) (5 x + 2)$
$= x = 2$ and $x = \frac{- 2}{5}$
The zeroes of the polynomials are $x = 2$ and $x = \frac{- 2}{5}$

Suggest Corrections

Similar questions

5 \sqrt{5} x^{2} + 30 x + 8 \sqrt{5}

(5 - 3 \sqrt{2})

(5 + 3 \sqrt{2})

5 x^{2} + 8 x + 3

- 21 x^{2} + 16 x + 5

\frac{- 3}{2 \sqrt{5}}, - \frac{1}{2}

Join BYJU'S Learning Program