Find the zeros of the quadratic polynomial $(6 x^{2} - 7 x - 3)$

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Solution

$6 x^{2} - 7 x - 3 = 0$

$\Rightarrow 6 x^{2} - 9 x + 2 x - 3 = 0$

$\Rightarrow 3 x (2 x - 3) + 1 (2 x - 3) = 0$

$\Rightarrow (2 x - 3) (3 x + 1) = 0$

$\Rightarrow 2 x - 3 = 0$ OR $3 x + 1 = 0$

$\Rightarrow x = \frac{3}{2}$ OR $x = - \frac{1}{3}$

Hence the zeroes of polynomial $(6 x^{2} - 7 x - 3)$ are

$\frac{3}{2}$ and $- \frac{1}{3}$ .

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6 x^{2} - 3 - 7 x

6 x^{2} - 3 - 7 x

Question 1 (iii)
Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients.

$6 x^{2} - 3 - 7 x$

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