Question

Find the zeros of the quadratic polynomial √3x² - 8x + 4√3.

Answer 1

Given quadratic equation = √3x² - 8x + 4√3 = 0
We should factorize the equation first.

By splitting the middle term, we get
=√3x²-6x-2x+4√3 = 0
= √3x(x-2√3)-2(x-2√3) = 0
= (√3x-2) (x-2√3) = 0
= (√3x-2) = 0 , (x-2√3) = 0
$⟹$ x = 2/√3 , x = 2√3.

Thus, the zeros of the given polynomial √3x² - 8x + 4√3 are 2/√3 and 2√3.