Question

Find the zetoes of cubic polynomials
$-x^3$
without drawing the graph of the polynomial.

Answer 1

$y=-x^3$
Let $f\left(x\right)=-x^3,$

Since, every cubic polynomial has at most three zeros.
Now, put $f\left(x\right)=0$
$\Rightarrow -x^3=0$

$\Rightarrow x^3=0$

$\Rightarrow x^3=0^3$

$\Rightarrow x=0$

i.e., the zeros of cubic polynomial '$-x^3$' are real and equal.

Therefore, zero of the polynomial $f\left(x\right)$ is only one .i.e.$0$.