Question

Find $\theta$, if $0\le \theta \le {90}^o$
$5\sin \theta =0$

Answer 1

The given trignometric function is $5\sin \theta =0$ that is

$\sin \theta =0........\left(1\right)$

We know that $\sin 0^o=0........\left(2\right)$

From equations 1 and 2 we get,

$\sin \theta =\sin 0^o\Rightarrow \theta =0^o$

Hence, $\theta =0^o$.