Question

Find three comsecutive natural numbers such that sum of the first and the second is 39 more than the third number.

Answer 1

$$\begin{gathered} \mathrm{Let}\mathrm{the}3\mathrm{consecutive}\mathrm{natural}\mathrm{numbers}\mathrm{be}\mathrm{x},\mathrm{x}+1\mathrm{and}\mathrm{x}+2. \\ \mathrm{Now},\mathrm{according}\mathrm{to}\mathrm{question}: \\ \mathrm{x}+\mathrm{x}+1=\mathrm{x}+2+39 \\ \Rightarrow 2\mathrm{x}+1=\mathrm{x}+41 \\ \Rightarrow 2\mathrm{x}-\mathrm{x}=41-1 \\ \Rightarrow \mathrm{x}=40 \\ \mathrm{So},\mathrm{required}\mathrm{numbers}\mathrm{are}: \\ 40,41\mathrm{and}42 \end{gathered}$$