Find three consecutive even numbers whose sum is 246.
Given that sum of three consecutive even numbers is 246.
Let three consecutive even numbers are x,x+2 and x+4.
Now,
x+(x+2)+(x+4)=246
⟹3x+6=246
⟹3x=246−6=240
⟹x=2403
⟹x=80
Hence, three consecutive even number are,
x=80
x+2=80+2=82
x+4=80+4=84
Therefore, the three consecutive even numbers are 80,82 and 84.