Question

Find three consecutive even numbers whose sum is $66$.

Answer 1

Let the smallest numbers be $X$

The other $2$ numbers are $(x+2)$ and $(x+4)$

Their sum is $66$:

$\begin{array}{c}x+\left(x+2\right)+\left(x+4\right)=66\\ x+x+2+x+4=66\\ 3x+6=66\\ 3x=60\\ x=20\end{array}$

Then,

We get smallest number$=x=20$

$2nd$ number$=x+2=20+2=22$

$3rd$ number$=x+4=20+4=24$