Question

Find three consecutive integers whose sum is equal to $366$.

Answer 1

Let the first number be $x$ then two consecutive numbers will be, $x+1$ and $x+2$, now we get the equation as,
$x+x+1+x+2=366$
$3x+3=366$
$3x=366-3$
$x=363/3$
$x=121$
As the first number of the three consecutive number $x=121$ so the next two numbers are $x+1=121+1$ = 122 and $x+2=121+2$ = 123.
The answer we get is
$121+122+123=366$
The answer is 121, 122 and 123.