Question

Find three consecutive natural number such that the sum of the first and second is 39 more than the third number.

Answer 1

Let the first number is x.
other numbers are (x+1), (x+2).
given that sum of the first and second numbers are 39 more than the third number.
x+(x+1)=(x+2)+39
2x+1=x+41
2x-x=41-1
x=40
three numbers are 40,41,42.