Find three consecutive numbers such that the sum of II and III number as it the first by 14

Let the first number be x Second be x+1 and third be x+2 According to the question : (X+1+X+2) X=14 2X+3 X=14 X=14 3 X=11 THEREFORE THE NUMBERS ARE 11,12 AND ...

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Standard VII

Mathematics

Number Properties (Language)

Find three co...

Question

Find three consecutive numbers such that the sum of the second and the third number exceeds the first by $14$ .

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Solution

Let the three consecutive numbers be $x, x + 1, x + 2$
Now, according to the question,
$\Rightarrow (x + 2 + x + 1) - (x) = 14$
$\Rightarrow 2 x + 3 - x = 14$
$\Rightarrow x = 14 - 3$
$\Rightarrow x = 11$
Therefore, the three consecutive numbers are $11, (11 + 1), (11 + 2)$ ie. $11, 12, 13$ .

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Find three consecutive numbers such that the sum of the second and the third number exceeds the first by 14.

Let the three consecutive numbers be x,x+1,x+2Now, according to the question,⇒(x+2+x+1)−(x)=14⇒2x+3−x=14⇒x=14−3⇒x=11Therefore, the three consecutive numbers are 11,(11+1),(11+2) ie. 11,12,13.

Find three consecutive numbers such that the sum of the second and the third number exceeds the first by $14$ .

Let the three consecutive numbers be $x, x + 1, x + 2$
Now, according to the question,
$\Rightarrow (x + 2 + x + 1) - (x) = 14$
$\Rightarrow 2 x + 3 - x = 14$
$\Rightarrow x = 14 - 3$
$\Rightarrow x = 11$
Therefore, the three consecutive numbers are $11, (11 + 1), (11 + 2)$ ie. $11, 12, 13$ .