Question

Find three consecutive numbers whose sum is. 108

Answer 1

x=first integer
x+1=second integer
x+1+1=third integer

(x)+(x+1)+(x+1+1)=108
3x+3=108
Let's isolate x.
Let's subtract 3 from both sides.
-3+3x+3=108-3
3x=105
Let's divide both sides by 3.
(3x)/3=105/3
x=35

35, 36, 37