Question

Find three consecutive odd numbers whose sum is $219$.

Answer 1

Let the three consecutive odd numbers be $x,x+2,x+4$.

Given, their sum $=219$

Therefore, $x+x+2+x+4=219$

$\Rightarrow 3x+6=219$

Subtract $6$ from both the sides,

$\Rightarrow 3x+6-6=219-6$

$\Rightarrow 3x=213$

$\Rightarrow x=71$

The other numbers are $x+2=71+2=73$ and $x+4=71+4=75$.

Therefore, threee odd numbers are $71,73$ and $75$.