Find three consecutive odd numbers whose sum is 219
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Solution
Let the 3 consecutive odd numbers be 2k+1,2k+3 and 2k+5 where k is an integer. Then sum of numbers = 2k+1+2k+3+2k+5= 6k+9= 219 so 6k = 210 k = 210/6= 35 The numbers aare therefore: 2k+1= 2(35)+1 = 71, 73,75 Answer:71,73,75