Question

Find three different solution of the each of the equation.

3x + 4y = 7

Answer 1

Given equation is $3x+4y=7$

If $x=1$ put in equation we get

(i)$3\times 1+4y=7$

$\Rightarrow 3+4y=7$

$\Rightarrow 4y=7-3$

$\Rightarrow 4y=4$

$\Rightarrow y=1$

$(1,1)$

If $x=2$ put in equation we get

(i)$3\times 2+4y=7$

$\Rightarrow 6+4y=7$

$\Rightarrow 4y=7-6$

$\Rightarrow 4y=1$

$\Rightarrow y=\frac{1}{4}$

$(2,\frac{1}{4})$

If $x=3$ put in equation we get

(iii)$3\times 3+4y=7$

$\Rightarrow 9+4y=7$

$\Rightarrow 4y=7-9$

$\Rightarrow 4y=-2$

$\Rightarrow y=-\frac{2}{4}$

$(3,-\frac{2}{4})$