Question

Find three different solution of the equation

10x + 11y = 21

Answer 1

Given equation $10x+11y=21$

(i)$10x+11y=21$

If $y=1$ put in equation we get

$10x+11\times 1=25$

$\Rightarrow 10x+11=21$

$\Rightarrow 10x=21-11=10$

$\Rightarrow x=1$

$(1,1)$

(ii)$10x+11y=21$

If $y=2$ put in equation we get

$10x+11\times 2=21$

$\Rightarrow 10x+22=21$

$\Rightarrow 10x=21-22=-1$

$\Rightarrow x=\frac{-1}{10}$

$(\frac{-1}{10},2)$

(iii)$10x+11y=21$

If $y=3$ put in equation we get

$10x+11\times 3=21$

$\Rightarrow 10x+33=21$

$\Rightarrow 10x=21-33=-12$

$\Rightarrow x=\frac{-12}{10}$

$(\frac{-12}{10},3)$