Question

Find three different solution of the equation

5x - 2y + 3 = 0

Answer 1

(i)$5x-2y+3=0$

If $x=0$ put we get

$5\times 0-2y+3=0$

$\Rightarrow -2y+3=0$

$\Rightarrow -2y=-3$

$\Rightarrow y=\frac{3}{2}$

$(0,\frac{3}{2})$

(ii)$5x-2y+3=0$

If $x=1$ put we get

$5\times 1-2y+3=0$

$\Rightarrow 5-2y+3=0$

$\Rightarrow -2y=-3-5=-8$

$\Rightarrow y=\frac{8}{2}=4$

$(1,4)$

(iii)$5x-2y+3=0$

If $y=0$ put we get

$5x-2\times 0+3=0$

$\Rightarrow 5x+3=0$

$\Rightarrow 5x=-3$

$\Rightarrow x=\frac{-3}{5}$

$(\frac{-3}{5},0)$