Let the numbers in G.P be a,ar,ar2
Given that a+ar+ar2=35 and a×ar×ar2=1000
a(1+r+r2)=35 and ar=10⇒a=10r
10r(1+r+r2)=35
⇒2r2−5r+2=0⇒2r2−4r−r+2=0
(2r−1)(r−2)=0
r=12 or 2
If r=12 then a=20 ....... As a=1012=20
The terms of G.P will be 20,20×12,20×122 i.e 20,10,5
If r=2 then a=5
The terms of G.P will be 5,5×2,5×22 i.e 5,10,20