Question

Find three rational numbers equivalent to:
$iii.\frac{-5}{9}$

Answer 1

Given, rational number is $\frac{-5}{9}$.
We know that,
On multiplying the numerator and denominator of a fraction with the same integer, the fraction value does not change.
$\therefore$ Required equivalent rational numbers.
$\frac{-5}{9}=\frac{-5\times 2}{9\times 2}=\frac{-10}{18}$
$\frac{-5}{9}=\frac{-5\times 3}{9\times 3}=\frac{-15}{27}$
$\frac{-5}{9}=\frac{-5\times 4}{9\times 4}=\frac{-20}{36}$

Hence $\frac{-10}{18},\frac{-15}{27}\text{and}\frac{-20}{36}$ are rational numbers equivalent to the given rational number $\frac{-5}{9}$.