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Question

Find three real numbers in GP whose sum is 30 and product is 216

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Solution

Let the numbers be,

ar,a,ar

Given,

ar×a×ar=216

a3=216

a=6

ar+a+ar=30

1r+1+r=5

r24r+1=0

r=2±3

Therefore the numbers are:

62±3,6,12±63

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