Question

Find time of flight and range of the projectile along the inclined plane as shown in figure $g=10m/s^2$

Answer 1

Time of flight $T=\frac{2u\sin \theta }{g}$

It is given that $u=20\sqrt{2}m/s$

So,

$T=\frac{2\times 20\sqrt{2}\sin 45}{10}$

$T=4s$

Range of projectile

$R=\frac{u^2\sin \theta }{2g}$

$R=\frac{{\left(20\sqrt{2}\right)}^2\sin 45}{20}$

$R=20\sqrt{2}m$