Question

Find, to the nearest tenth, the mean absolute deviation for the set
$2,5,7,9,1,3,4,2,6,7,11,5,8,2,4$.

• A. $2.3$
• B. $1.3$
• C. $2.4$
• D. $1.4$

Answer 1

The correct option is A $2.3$

$X$	2	5	7	9	1	3	4	2	6	7	11	5	8	2	4
$|X-\overline{X}|$	3.06	0.06	1.94	3.94	4.06	2.06	1.06	3.06	0.94	1.94	5.94	0.06	2.94	3.06	1.06

$\overline{x}=\frac{\sum x}{N}=\frac{76}{15}=5.06$

Mean Absolute Deviation$=\frac{\sum |x-\overline{x}|}{N}=\frac{35.18}{15}=2.3$