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Structural Isomerism

Find total po...

Question

Find total possible stereoisomer for the molecule [Ma $_{2}$ bcde] $^{n \pm}$ (where a.b,c,d.. are simple monodentate ligand having no chiral centre).

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Solution

In the complex [Ma $_{2}$ bcde] ,
Total geometrical isomers = 9
Optical isomers = 15 (12 optical active, 3 optical inactive)
Steroisomers = 15
Thus total possible stereoisomer for the molecule [Ma $_{2}$ bcde] $^{n \pm}$ is 15.

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