Question

Find two consecutive multiples of 3 whose product is 648.

Answer 1

Let two consecutive multiples of 3 be x and (x+3)

According to question,

$x\times (x+3)$= 648

➡ x² + 3x = 648

➡ x² + 3x -648 = 0

➡ x² + 27x - 24x -648 = 0

➡ x ( x + 27 ) -24 ( x +27)

➡ ( x - 24) ( x + 27)

➡ x = 24 and x = -27

so, we take x = 24.

Required multiples of 3

➡ x = 24

➡ x +3 = 24+3 = 27.

Hence, two consecutive multiples of three are $24$ and $27$