CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find two consecutive positive even integers whose product is 288.

Open in App
Solution

Let the two consecutive positive integer be x and x+2
According to the given condition,
X(x+2)=288
x squared plus 2 x minus 288 equals 0
x squared plus 18 x minus 16 x minus 288 equals 0
x(x+18)-16(x+18)=0
(x+18)(x-16)=0
x+18=0 or x-16=0
x=-18 or x=16
Since the integers are positive
We wil take x=16
Therefore another positive integer will be 16+2=18
Hence the positive integers are 16 and 18


flag
Suggest Corrections
thumbs-up
30
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Solving QE by Factorisation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon