Question

Find two numbers in the ratio of $7:12$ so that the greater exceeds the less by $275$.

Answer 1

The ratio of two numbers are $7:12$

Let $7x$ and $12x$ be the two required number.

According to the question,

$\Rightarrow$ $12x-7x=275$

$\Rightarrow$ $5x=275$

$\therefore$ $x=55$

$\Rightarrow$ $7x=7\times 55=385$

$\Rightarrow$ $12x=12\times 55=660$

$\therefore$ The required two numbers are $385$ and $660$.