Consider the given equation,
3x−2y=5
put x=0 then,
3×0−2y=5
y=−52
Now, put y=0 then,
3x−2×0=5
x=53
Find out which of the following equations have x=1, y=2 as solution. x + 2y = 5 2y - 3x + 3 = 0 3x + 4y - 8 = 0 [4 MARKS]