Find two solutions of 3x+4y=12
Finding two solution for equation 3x+4y=12:
Putting the value of x=0 in equation 3x+4y=12
⇒30+4y=12
⇒4y=12
⇒y=3
Thus, 0,3 is a solution of equation 3x+4y=12
Putting the value of y=0 in equation 3x+4y=12
⇒3x+40=12
⇒3x=12
⇒x=4
Thus, 4,0 is a solution of equation 3x+4y=12
Therefore, 0,3,4,0 are two solution of equation 3x+4y=12
Find the X intercept of 3x - 4y = 12