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Question

Find limx0 f(x) and limx1 f(x) where f(x)= {2x+3x03(x+1)x>0

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Solution

Here f(x) = {2x+3x03(x+1)x>0

Now limx0 f(x) = limx0 2x+3=2×0+3 = 3

limx0f(x)=limx0 3(x+1) = 3 (1+1)

= 3 × 2 = 6.


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