wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find unit vector perpendicular to the plane of the vectors,
A=^i2^j+^k and B=2^i^k.

Open in App
Solution

The vector perpendicular to these vectors is-

n=A×B=(i2j+k)×(2ik)

n=2i+3j+4k

n=4+9+16=29

hence, unit vector is

^n=2i+3j+4k29

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Vector Intuition
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon