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Standard XII

Chemistry

Characteristics of Chemical Equilibrium

Find VA - VB ...

Question

Find $V_{A} - V_{B}$ in the given figure ?

- 15 V

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10 V

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11 V

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15 V

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Solution

The correct option is C $11 V$

Using KVL,

$V_{B} - L \frac{d i}{d t} - i R - V_{A} = 0$

$V_{B} - [5 (- 3)] - (2 \times 2) - V_{A} = 0$

$V_{B} - V_{A} = - 11 V$

$V_{A} - V_{B} = 11 V$

 Hence, $(C)$ is the correct answer.

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Find VA−VB in the given figure ?

The correct option is C 11 V Using KVL, VB−Ldidt−iR−VA=0 VB−[5(−3)]−(2×2)−VA=0 VB−VA=−11 V VA−VB=11 V  Hence, (C) is the correct answer.

Find $V_{A} - V_{B}$ in the given figure ?

The correct option is C $11 V$

Using KVL,

$V_{B} - L \frac{d i}{d t} - i R - V_{A} = 0$

$V_{B} - [5 (- 3)] - (2 \times 2) - V_{A} = 0$

$V_{B} - V_{A} = - 11 V$

$V_{A} - V_{B} = 11 V$

 Hence, $(C)$ is the correct answer.