Question

Find value of

${\sin }^{2}A{\cot }^{2}A+{\cos }^{2}A{\tan }^{2}A$

Answer 1

${\sin }^{2}A{\cot }^{2}A+{\cos }^{2}A{\tan }^{2}A=$ ${\sin }^{2}A\frac{{\cos }^{2}A}{{\sin }^{2}A}+{\cos }^{2}A\frac{{\sin }^{2}A}{{\cos }^{2}A}={\cos }^{2}A+{\sin }^{2}A=1$