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Byju's Answer
Standard XII
Mathematics
Basic Inverse Trigonometric Functions
find value of...
Question
find value of sin
2
11.25 + sin
2
33.75 + sin
2
56.25 + sin
2
78.75
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Solution
sin
2
11
.
25
+
sin
2
33
.
75
+
sin
2
56
.
25
+
sin
2
78
.
75
=
sin
2
11
.
25
+
sin
2
33
.
75
+
sin
2
90
-
33
.
75
+
sin
2
90
-
11
.
25
=
sin
2
11
.
25
+
sin
2
33
.
75
+
cos
2
33
.
75
+
cos
2
11
.
25
Since
sin
90
-
x
=
cos
x
=
sin
2
11
.
25
+
cos
2
11
.
25
+
sin
2
33
.
75
+
cos
2
33
.
75
=
1
+
1
Since
sin
2
x
+
cos
2
x
=
1
=
2
ANS
.
.
.
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